5y^2+4+1y=4

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Solution for 5y^2+4+1y=4 equation:


Simplifying
5y2 + 4 + 1y = 4

Reorder the terms:
4 + 1y + 5y2 = 4

Add '-4' to each side of the equation.
4 + 1y + -4 + 5y2 = 4 + -4

Reorder the terms:
4 + -4 + 1y + 5y2 = 4 + -4

Combine like terms: 4 + -4 = 0
0 + 1y + 5y2 = 4 + -4
1y + 5y2 = 4 + -4

Combine like terms: 4 + -4 = 0
1y + 5y2 = 0

Solving
1y + 5y2 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), 'y'.
y(1 + 5y) = 0

Subproblem 1

Set the factor 'y' equal to zero and attempt to solve: Simplifying y = 0 Solving y = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y = 0

Subproblem 2

Set the factor '(1 + 5y)' equal to zero and attempt to solve: Simplifying 1 + 5y = 0 Solving 1 + 5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 5y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 5y = 0 + -1 5y = 0 + -1 Combine like terms: 0 + -1 = -1 5y = -1 Divide each side by '5'. y = -0.2 Simplifying y = -0.2

Solution

y = {0, -0.2}

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